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For an ideal gas :...

For an ideal gas :

A

the change in internal energy in a constant pressure process from temperature `T_1 toT_2` is equal to `nC_v(T_2-T_1),` where `C_v` is the molar specific heat at constant volume and n the number of moles of the gas.

B

the change in internal energy of the gas and the work done by the gas are equal in magnitude in an adiabatic process.

C

the internal energy does not change in an isothermal process.

D

no heat is added or removed in an adiabatic process.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D

(a,b,c,d)
(a) For all thermal processes.
`DeltaU=nC_vDeltaT where DeltaT=(T_2-T_1)`
(b) According to first law of thermodynamics.
`DeltaQ=DeltaU+DeltaW`
In an adiabatic processes `DeltaQ=0.`
or, `0=DeltaU+DeltaW`
or, `|DeltaU|=|DeltaW|`
(c) In the isothermal process, `DeltaT=0`
`:' DeltaU=0`
(d) In the adiabatic process, `DeltaQ=0.`
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