Two glass bulbs of equal volume are connected by a narrow tube and are filled with a gas at `0^@C` and a pressure of 76cm of mercury. One of the bulbs is then placed in melting ice and the other is placed in a water bath maintained at `62^@C`. What is the new value of the pressure inside the bulbs? The volume of the connecting tube is negligible.

Answer

C

Explanation

Let x moles shift from high temperature side to low
temperature side.
for left bulb `PV=nRT`
`76xxV=nRxx273` Initially
`P'xxV=(n+x)Rxx273` Finally
Dividing, we get
`P'/76=(n+x)/n…..(i)`


For right bulb
`76xxV=nRxx273` initially
`P'xxV=(n-x)Rxx335` Finally
On dividing,
`P'/76=(n-x)/xx335/273.....(ii)`
`rArrn=608/62x....(iii)`
Substituting the value of (iii) in (i), we get
`P'/76=1+62/608`
`rArrP'=670/608xx76=83.75 cmHg`