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Statement-1: The temperature dependence ...

Statement-1: The temperature dependence of resistance is usually given as `R=R_0(1+alphaDeltaT)`. The resistance of a wire changes from `100Omega to 150Omega` when its temperature is increased from `27^@C to 227^@C`. This implies that `alpha=2.5xx10^-3//^@C`.
Statement 2: `R=R_0(1+alphaDeltaT)` is valid only when the change in the temperature `DeltaT` is small and `DeltaR=(R-R_0) lt ltR_0`.

A

Statement-1 is True,Statement-2 is True, Statement-2 is a correct explanation for Statement-1

B

Statement-1 is True, Statement-2 is True, Statement-2 is not a correct explanation for Statement--1

C

Statement-1 is False, Statement-2 is True

D

Stement-1 is True, Statement-2 is False.

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The correct Answer is:
To solve the problem, we need to analyze the two statements provided regarding the temperature dependence of resistance in a wire. ### Step 1: Understand the formula for resistance change The formula given is: \[ R = R_0(1 + \alpha \Delta T) \] where: - \( R \) is the resistance at the new temperature, - \( R_0 \) is the initial resistance, - \( \alpha \) is the temperature coefficient of resistance, - \( \Delta T \) is the change in temperature. ### Step 2: Calculate the change in temperature The initial temperature is \( 27^\circ C \) and the final temperature is \( 227^\circ C \). Therefore, the change in temperature (\( \Delta T \)) is: \[ \Delta T = 227^\circ C - 27^\circ C = 200^\circ C \] ### Step 3: Calculate the change in resistance The resistance changes from \( 100 \Omega \) to \( 150 \Omega \). Thus, the change in resistance (\( \Delta R \)) is: \[ \Delta R = R - R_0 = 150 \Omega - 100 \Omega = 50 \Omega \] ### Step 4: Substitute values into the resistance formula Using the formula: \[ 150 = 100(1 + \alpha \cdot 200) \] ### Step 5: Solve for \( \alpha \) Rearranging the equation: \[ 1 + \alpha \cdot 200 = \frac{150}{100} \] \[ 1 + \alpha \cdot 200 = 1.5 \] \[ \alpha \cdot 200 = 0.5 \] \[ \alpha = \frac{0.5}{200} = 0.0025 \, ^\circ C^{-1} = 2.5 \times 10^{-3} \, ^\circ C^{-1} \] ### Step 6: Analyze the validity of the statements - **Statement 1**: The calculation shows that \( \alpha = 2.5 \times 10^{-3} \, ^\circ C^{-1} \) is correct based on the given resistance change. However, the formula \( R = R_0(1 + \alpha \Delta T) \) is typically valid for small changes in temperature. - **Statement 2**: It states that the formula is valid only when \( \Delta T \) is small and \( \Delta R \) is much smaller than \( R_0 \). Given that \( \Delta T = 200^\circ C \) is not small, this statement is correct. ### Conclusion - **Statement 1** is incorrect because the temperature change is significant, which violates the condition for the formula's validity. - **Statement 2** is correct as it accurately describes the limitations of the formula. Thus, the correct conclusion is that **Statement 1 is false and Statement 2 is true**.

To solve the problem, we need to analyze the two statements provided regarding the temperature dependence of resistance in a wire. ### Step 1: Understand the formula for resistance change The formula given is: \[ R = R_0(1 + \alpha \Delta T) \] where: - \( R \) is the resistance at the new temperature, - \( R_0 \) is the initial resistance, ...
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