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If the heat fo dissolution of anhydrous ...

If the heat fo dissolution of anhydrous `CuSO_(4)` and `CuSO_(4).5H_(2)O` is `-15.89 kcal` and `2.80 kcal`, respectively, then the heat of hydration of `CuSO_(4)` to form `CuSO_(4).5H_(2)O` is

A

`-13.09` kcal

B

`-18.69` kcal

C

`+13.09`kcal

D

`+18.69` kcal

Text Solution

Verified by Experts

The correct Answer is:
B
(i) `CuSO_4+aqto CuSO_4(ag)DeltaH_1=-1589kcal`
(ii) `CuSO_4.5H_2O+aqtoCuSO_4(aq)DeltaH_2=+2.8kcal`
Eq.(i) -Eq.(ii) gives
`DeltaH=-1869kcal (DeltaH=DeltaH_1-DeltaH_2)`
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If the heat fo dissolution of anhydrous CuSO_(4) and CuSO_(4).5H_(2)O is -15.89 kcal and 2.80 kcal , respectively, then the heat of hydration fo CuSO_(4) to form CuSO_(4).5H_(2)O is

The heat of solution of anhydrous CuSO_(4) and CuSO_(4).5H_(2)O are -15.89 and 2.80 Kcal mol^(-1) respectively. What will be the heat of hydration of anhydrous CuSO_(4) ?

In solid CuSO_(4).5H_(2)O

Heat of sol^(n) of CuSO_(4) (s) and CuSO_(4) . 5 H_(2) O is 15.9 and 19.3 kJ/mol respectively . Find the heat of hydration of CuSO_(4) (s)

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The heat of solution of anhydrous CuSO_(4) is -66.5 kJ and that of CuSO_(4).5H_(2)O is 11.7 kJ . Calculate is the heat of hydration of CuSO_(4) .

CuSO_(4)*5H_(2)O belongs to

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