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When ammonia is heated with cupric oxide...

When ammonia is heated with cupric oxide, a molecule of ammonia will

A

gain 3 electrons

B

lose 3 electrons

C

gain 2 electrons

D

lose 2 electrons

Text Solution

Verified by Experts

The correct Answer is:
B
`NH_3` reduces cupric oxide CuO to forming `N_2`.
`2NH_3 +3CuOto 3Cu+3H_2O+N_2uarr`
`2NH_3` molecules lose `6e^(-)`.
`therefore ` One `NH_3` will lose `3e^(-)`.
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