The vapour pressure of a solution (P) and the vapour pressure of the solvent `(P^(@))` are related to each others as `(x_(1)` is the mole fraction of solvent)

Options

A. `p=p^(@)X_(2)`
B. `p=p^(@)X_(1)`
C. `p^(@)=p.X_(1)`
D. `p^(@)=p.X_(2)`.

Answer

B

Explanation

According to Raoult's law, Vapour pressure of solution `(p)=` vapour pressure of pure solvent `(p^@)` x mole fraction of solvent `(X_1)`
`therefore " " p=p^(@)X_1`.