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The volume of oxygen evolved at STP by d...

The volume of oxygen evolved at STP by decomposition of `0.68g` '20 volume ' hydrogen peroxide solution is

A

2.24mL

B

22.4mL

C

224mL

D

2240mL

Text Solution

Verified by Experts

The correct Answer is:
C

`underset(=2xx34=68g)(underset(2 "mol")(2H_(2))O_(2))to2H_(2)O+underset(22400"mL")underset(1"mol")(O_(2))`
`therefore` At STP , `68 gH_2O_2` produced `O_2=22400m L`
`therefore` At STP , `0.68g H_2O_2` will produce
`O_2=(22400xx0.68)/(68)=224mL`
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