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inte^(x)((x-1))/(x^(2))dx is equal to...

`inte^(x)((x-1))/(x^(2))dx` is equal to

A

`(e^(x))/(x^(2))+C`

B

`(-e^(x))/(x^(2))+C`

C

`(e^(x))/(x)+C`

D

`(-e^(x))/(x)+C`

Text Solution

Verified by Experts

The correct Answer is:
C
`inte^(x)((x-1)/(x^(2)))dx=inte^(x)((1)/(x)-(1)/(x^(2)))dx=(e^(x))/(x)+c`
`" "[because int e^(x)[f(x)+f'(x)]dx=e^(x)f(x)+C]`
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