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The vector equation of the line (x-2)/(2...

The vector equation of the line `(x-2)/(2)=(2y-5)/(-3),z=-1` is `r=(2hati+(5)/(2)hatj-hatk)+lambda(2hati-3/2hatj+xhatk)` where x is equal to

A

0

B

1

C

2

D

3

Text Solution

Verified by Experts

The correct Answer is:
A
The given equation of line is `(x-2)/(2)=(2y-5)/(-3),z=-1`
`Rightarrow (x-2)/(2)=(y-(5)/(2))/(-(3)/(2))=(z+1)/(0)`
So its vector is `vecr=(2hati+5/2hatj-hatk)+lambda(2hati-3/2hatij+0hatk)`
Hence, x=0
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