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For the lines L1 ; vec a+t(vec b+vec c) ...

For the lines `L_1 ; vec a+t(vec b+vec c) and L_2 ; vec r=vec b+s(vec c+vec a)` then `L_1 and L_2` 1ntersect at

A

a

B

b

C

a b+c

D

a 2b

Text Solution

Verified by Experts

The correct Answer is:
C
Since the lines intersect `therefore a+t(b+c)=b+s(c+a)`
We easily get t=1, s=1
Hence point of intersection is a+b+c.
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