Home
Class 12
MATHS
The distance between two parallel lines ...

The distance between two parallel lines can be taken out by the formula

A

`d=|(b.(a_(2)-a_(1)))/(|b|)|`

B

`d=|(b.(a_(2)-a_(1)))/(|a_(2)-a_(1)|)|`

C

`d=|(b.(a_(2)-a_(1)))/(|a_(2)-a_(1)|)|`

D

`d=|(bxx(a_(2)-a_(1)))/(|b|)|`

Text Solution

Verified by Experts

The correct Answer is:
D
The distance between the given parallel lines is `d=|(b xx(a_(2) -a_(1)))/(|b|)|`
Promotional Banner

Topper's Solved these Questions

  • LINE

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise Exercise 2(Miscellaneous Problems)|30 Videos

  • LINE

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET Corner|3 Videos

  • INTEGRATION

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET Corner|30 Videos

  • Linear Programming

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET Corner|13 Videos

Similar Questions

Explore conceptually related problems

Distance between two parallel planes

Shortest distance between two parallel lines in vector + cartesian form

The distance between the parallel lines y=x +a, y =x+ b is

The distance between two parallel lines is p^(1)-p equation of one line is x cos alpha+y sin alpha=p then the equation of the 2^(nd) line is

Transversal to two parallel lines:

Distance OF point from the line || Distance between two parallel lines || Distance between two skew line || Illustration on cross product

The distance between the two parallel lines is 1 unit. A point A is chosen to lie between the lines at a distance 'd' from one of them Triangle ABC is equilateral with B on one line and C on the other parallel line. The length of the side of the equilateral triangle is

Statement 1: The shortest distance between the lines x/2=y/(-1)=z/2 and (x-1)/(-2)=(y-1)/-2=(z-1)/4 is sqrt(2) . Statement 2: The shortest distance between two parallel lines is the perpendicular distance from any point on one of the lines to the other line.

Find the distance between two parallel sides if AB||CD.