The shortest distance between the skew lines `bar(r) = bar(a_(1)) + lambda bar(b_(1)) "and" bar(r) = bar(a_(2)) + mu bar(b_(2))` is

Options

A. `d=|((b_(1)-b_(2)).(a_(1)xxa_2))/(a_(1)xxa_(2))|`
B. `d=|((b_(1).b_(2)).(a_(1)-a_2))/(|b_(1)||b_2|)|`
C. `d=|((b_(1)xxb_(2)).(a_(2)-a_1))/(|b_(1)|xx|b_2|)|`
D. `d=|((b_(1)xxb_(2)).(a_(2)xxa_1))/(|b_(1)xxb_2||a_1xxb_2)|`

Answer

C

Explanation

`therefore ` The shortest distance between two skew lines is `d=|((b_(1) xxb_(2)).(a_(1)xxa_(1)))/(|b_(1) xx b_(2)|)|`