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The point of the line (x-2)/(1)=(y+3)/(-...

The point of the line `(x-2)/(1)=(y+3)/(-2)=(z+5)/(-2)` at a distance of 6 from the point (2,-3,-5) is

A

(3,-5,-3)

B

(4,-7,-9)

C

(0,2,-1)

D

(-3,5,3)

Text Solution

Verified by Experts

The correct Answer is:
B
Direction of the given line is
`(1)/(3)-(2)/(3),-(2)/(3)`
Hence , the equation of line passing throught `(2,-3,-5)` and parallel to the given line is `(x-2)/(1//3) = (y+3)/(-2//3) =(z+5)/( - 2//3) = r`
`therefore` Points is `(2+(r)/(3), - 3-(2r)/(3), -5-(2r)/(3))`
But is given ` " " r = pm 6`
`therefore` Points are (4,-7,-9) and (0,-1,-1)
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