Home
Class 12
MATHS
The length of the perpendicular from P(1...

The length of the perpendicular from P(1,6,3) to the line `x/1=(y-1)/(2)=(z-2)/(3) is `

A

` 3 `

B

` sqrt ( 11 ) `

C

` sqrt ( 13 ) `

D

` 5 `

Text Solution

Verified by Experts

The correct Answer is:
C

Given ` (x ) / ( 1 ) = ( y - 1 ) / ( 2 ) = ( z - 2 ) / ( 3 ) = lamda `
Any point on the line is ` P ( lamda , 2 lamda + 1 , 3 lamda + 2 ) `
Therefore, direction ratios of PQ are ` ( lamda - 1 , 2 lamda - 5, 3lamda - 1 ) `
` because PQ ` is perpendicular to the given line
Therefore, ` 1 ( lamda - 1 ) + 2 ( 2lamda - 5 ) + 3 ( 3lamda - 1 ) = 0 `
` " "[ because a - 1 a _ 2 + b _ 1 b _ 2 + c _ 1 c _ 2 = 0 ] `
` rArr lamda = 1 `
` therefore ` The coordinates of P are ` ( 1, 3, 5 )`
` therefore ` Length of perpendicular , QP
` = sqrt (( 1 - 1) ^ 2 + (3 - 6 ) ^ 2 + ( 5 - 3) ^ 2) = sqrt ( 13 ) `
Promotional Banner

Topper's Solved these Questions

  • LINE

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET Corner|3 Videos
  • LINE

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET Corner|3 Videos
  • INTEGRATION

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET Corner|30 Videos
  • Linear Programming

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET Corner|13 Videos

Similar Questions

Explore conceptually related problems

The length of the perpendicular from P(1,0,2) on the line (x+1)/(3)=(y-2)/(-2)=(z+1)/(-1) is

Find the equations of the perpendicular from the point (1,6,3) to the line (x)/(1)=(y-1)/(2)=(z-2)/(3). Find also the coordinates of the foot of perpendicular.

The length of the perpendicular drawn from (1,2,3) to the line (x-6)/(3)=(y-7)/(2)=(z-7)/(-2) is a.4 b.5c.6d.7

Find the length of the perpendicular from ( 3,2,1) to the line (x - 7) /(-2) = (y - 7)/(2) = (z - 6 ) /(3) .

Find the length of the perpendicular from the point (1,2,3) to the line (x-6)/(3)=(y-7)/(2)=(z-7)/(-2)

The foot of the perpendicular from (2,4,-1) to the line (x+5)/(1)=(y+3)/(4)=(z-6)/(-9) is

MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-LINE-Exercise 2(Miscellaneous Problems)
  1. Find the vector and the cartesian equations of the line that passes t...

    Text Solution

    |

  2. Find the equation of the perpendicular drawn from (2,4,-1) to the line...

    Text Solution

    |

  3. The length of the perpendicular from P(1,6,3) to the line x/1=(y-1)/(2...

    Text Solution

    |

  4. The equation of a line which passes through the point ( 1, 2...

    Text Solution

    |

  5. P is a point on the line segment joining the points (3, 2, ...

    Text Solution

    |

  6. The equaton of the line in vector and cartesian from that pas...

    Text Solution

    |

  7. Find the vector and the cartesian equations of the lines that passes ...

    Text Solution

    |

  8. The equation of a line 4x-4y-z+11=0=x+2y-z-1 can be put as

    Text Solution

    |

  9. The line (x-2)/3=(y+1)/2=(z-1)/1 intersects the curve x y=c^(I2),z=0 i...

    Text Solution

    |

  10. the lines (x-2)/1 = (y-3)/1 = (z-4)/-k and (x-1)/k = (y-4)/1 = (z-5)/1...

    Text Solution

    |

  11. Find the equation of the perpendicular from point (3,-1,11) to line x...

    Text Solution

    |

  12. The line passing through the points (5,1,a) and (3,b,1) crosses the y...

    Text Solution

    |

  13. If the straight lines (x-1)/k=(y-2)/2=(z-3)/3 and (x-2)/3=(y-3)/k=(z-...

    Text Solution

    |

  14. Consider the line L 1 : (x+1)/3=( y-2)/1= (z+1)/2, L 2 : (x-2)/1=(...

    Text Solution

    |

  15. Match the following columns.

    Text Solution

    |

  16. Find the equation of a line passing through (1,-1,0) and parallel to t...

    Text Solution

    |

  17. The direction cosines of the line x-y+2z=5, 3x+y+z=6 are

    Text Solution

    |

  18. The length of the perpendicular drawn from (1,2,3) to the line (x-6)...

    Text Solution

    |

  19. The straight line (x-3)/3=(y-2)/1=(z-1)/0 is Parallel to x-axis Parall...

    Text Solution

    |

  20. If the lines (x-1)/2=(y+1)/3=(z-1)/4 and (x-3)/1=(y-k)/2=z/1 intersec...

    Text Solution

    |