Find the equation of a line passing through `(1,-1,0)` and parallel to the line `(x-2)/3=(2y+1)/2=(5-z)/1`

Options

A. ` ( x - 1 ) / ( 3 ) = ( y + 1 ) / ( 2 ) = ( z- 0 )/ ( - 1 ) `
B. ` ( x - 1 ) / ( 3 ) = ( y + 1 ) / ( 1 ) = ( z - 0 ) / ( - 1 ) `
C. ` ( x - 1 ) /( 3 ) = ( y + 1 ) / ( 1 ) = ( z - 0 ) / ( 1 ) `
D. ` ( x - 1 ) / ( 3 ) = ( y + 1 ) / ( 2 ) = ( z - 0 ) /( 1 ) `

Answer

C

Explanation

The equation of the given line can be rewritten as
` ( x - 2 ) / ( 3) = ( y + ( 1 ) / ( 2 )) / ( 1 ) = ( z - 5 )/ ( 1 ) `
direction ratios are 3, 1, 1
Hence, equation of required line
` ( x- 1) / ( 3 ) = ( y + 1 ) / ( 1 ) = ( z - 0 ) / ( 1 ) `