When threee capacitors of equal capacities are connected in parallel and one of the same capacity is connected in series withs its combination . The resultant capacity is `3.75 muF`. The capacity of each capacitor is

Options

A. `5 muF`
B. `6 muF`
C. `7 muF`
D. `8 muF`

Answer

C

Explanation

Net capacitance between A and B is
`C' = C + C + C = 3C`
Net capacitance between A and D is
`C_(eq) = (3C^(2))/(4C)`
`rArr C_(eq) = (3C)/(4)`

`:. C = (4C_(eq))/(3) = (04 xx 3.75)/(3)`
`:. C = 4 xx 125 = 5.00 muF`