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The polarising angle the transparent m...

The polarising angle the transparent medium is `'theta'` and 'v' is the speed of light in that medium. Then the relation between `'theta'` and 'v' is
(c = velocity of light in air)

A

`theta = tan^(-1)(v/c)`

B

`theta = cot^(-1)(v/c)`

C

`theta = sin^(-1) (v/c)`

D

`theta = cos^(-1) (v/c)`

Text Solution

Verified by Experts

The correct Answer is:
B
From the relation, `tan theta = mu = c/v`
`rArr cot theta = v/c`
`:. theta = cot^(-1) 'v/c`
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