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The magnetic moment of electron due t...

The magnetic moment of electron due to orbital motion is proportional to
(n= principle quantum numbers)

A

`1/(n^(2))`

B

`1/n`

C

`n^(2)`

D

n

Text Solution

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The correct Answer is:
D

Magnetic moment is given as,
magnetic moment `(M_(0)) = (e )/(2m_(e)) xx L`
where, `e =` electronic charge ,
`m_(e)` = mass of electron
and `L =` orbital angular momentum,
As, we know `L = (nh)/(2pi) "…."(i)`
where , n = principal quantum number
and `h =` Plancks constant.
Therefore, from relation (i) and (ii), we get `M_(0) prop n`.
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