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The ratio of binding energy of a satel...

The ratio of binding energy of a satellite at rest on earth's surface to the binding energy of a satellite of same mass revolving around of the earth at a height h above the earth's surface is (R = radius of the earth).

A

`(2(R+h))/(R )`

B

`(R + h)/(2)`

C

` (R + h)/(R )`

D

`(R )/(R + h)`

Text Solution

Verified by Experts

The correct Answer is:
A

Binding energy on the surface of the earth is
`E_1 = (GM)/(r ) "…"(i)`
Binding energy of revolving satellite at a height h is
`E_(2) = (GMm)/(2(R + h)) "…."(ii)`
From Eqs. (i) and (ii), we get
`:. (E_(1))/(E_2) = (2(R + h))/(R )`
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