Calculate the de-Broglie wavelength of an electron moving with one fifth of the speed of light. Neglect relativistic effects. `(h=6.63 xx 10^(-34) J.s., c=3xx10^(8)m//s`, mass of electron`=9xx10^(-31)kg)`

Explanation

Given : Velocity of electron,
`v=(c )/(5)=(3xx10^(8))/(5)`
`=0.6xx10^(8)ms^(-1)`
Planck's constant, `h=6.63xx10^(-34)J-s`
and, Broglie mass of mass fo electron, `m_(e)=9xx10^(31)kg`
de-Broglie wavelength of a particle is given `lambda=(h)/(mv)`
For an electron, `lambda=(h)/(m_(e)v)`
`=(6.63xx10^(-34))/(9xx10^(-31)xx0.6 xx 10^(8))`
`=1.227 xx 10^(-11) m`
`=0.123` Å