`(e^(x))/(logx)` का अवकल गुणांक x के सापेक्ष निकालें ।

Explanation

माना कि `y=(e^(x))/(logx)`
अब , `(dy)/(dx)=(d)/(dx)((e^(x))/(logx))=(logx*(d)/(dx)(e^(x))-e^(x)*(d)/(dx)(logx))/((logx)^(2))`
`=(logx*e^(x)-e^(x)*(1)/(x))/((logx)^(2))=(xe^(x)logx-e^(x))/(x(logx)^(2))=(e^(x)(xlogx-1))/(x(logx)^(2))`