यदि `x=a(theta-sintheta),y=a(1-costheta)`,`theta=(pi)/(2)` पर `(dy)/(dx)` निकालें ।

Explanation

दिया है, `x=a(theta-sintheta)rArr(dx)/(d theta)=a(1-costheta)`
तथा `y=a(1-costheta)rArr(dy)/(d theta)=asin theta`
`therefore(dy)/(dx)=(dy//d theta)/(dx//d theta)=(a sintheta)/(a(1-costheta))=(sintheta)/(1-cos theta)`
`theta=(pi)/(2)`, पर `(dy)/(dx)=("sin"(pi)/(2))/(1-"cos"(pi)/(2))=1`