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0.7 g of iron reacts directly with 0.4 g...

`0.7 g` of iron reacts directly with `0.4 g` of sulphur to form ferrous sulphide. If `2.8 g` of iron is dissolved in dilute `HCl` and excess of sodium sulphide solution is added, `4.4 g` of iron sulphide is precipitated. Prove the law of constant composition.

Text Solution

Verified by Experts

The ratio of the weight of iron and sulphur in the first sample of the compound is `Fe : S : : 0.7 : 0.4` or `7 : 4`.
According to the second experiment, `2.8 g` or iron gives `4.4 g` ferrous sulphide, or `2.8 g Fe` combines with `S = 4.4 - 2.8 = 1.6 g`
Therefore, the ratio of the weights of `Fe : S : : 2.8 : 1.6` or `7 : 4`.
Since the ratio of the weights of the two elements is same both the cases, the law of constant composition is true.
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