Home
Class 11
CHEMISTRY
When a mixture of 10 moles of SO(2) and ...

When a mixture of 10 moles of `SO_(2)` and 15 moles of `O_(2)` was passed over catalyst, 8 moles of `SO_(3)` was formed. How many moles of `SO_(2)` and `O_(2)` did not enter into combination?

Text Solution

Verified by Experts

`2SO_(2)` `+` `O_(2) rarr 2SO_(3)`
Initial `10 "mol"` `15 "mol"` 0
Final `10 - 2x` `15 - x` `2x`
`2 x = 8`
`x = 4`
Moles of `SO_(2)` left `= 10 - 2 xx 4 = 2 "mol"`
Mole of `O_(2)` left` = 15 - 4 = 11 " mol"`
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS AND MOLE CONCEPT

    CENGAGE CHEMISTRY|Exercise Ex 1.1 Objective Questions|6 Videos

  • SOME BASIC CONCEPTS AND MOLE CONCEPT

    CENGAGE CHEMISTRY|Exercise Ex 1.1 Objective Questions (Single Correct)|3 Videos

  • S-BLOCK GROUP 2 - ALKALINE EARTH METALS

    CENGAGE CHEMISTRY|Exercise Ex 5.1 Objective|2 Videos

  • STATES OF MATTER

    CENGAGE CHEMISTRY|Exercise Exercises (Ture False)|25 Videos

Similar Questions

Explore conceptually related problems

When a mixture of 10 moles of SO_(2) and 16 moles of O_(2) were passed over a catalyst, 8 moles of SO_(3) were formed at equilibrium. The number of SO_(2) and O_(2) remaining unreacted were:

When a mixture consisting of 10 moles of SO_2 and 16 moles of O_2 were passed over a catalyst , 8 mole of SO_3 were formed at equilibrium.The number of moles of SO_2 and O_2 which did not enter into reation were :

10 "mole of" kSO_(2) and 15 "mole of" O_(2) were passed over catalyst to produce 8 "mole of" SO_(3) . The ratio of SO_(2) and SO_(3) moles in mixture is:

10 moles SO_(2) and 15 moles O_(2) were allowed to react over a suitable catalyst. 8 moles of SO_(3) were formed. The remaining moles of SO_(2) and O_(2) respectively are -

1 mole of [OH^(-)] is present in how many moles of H_(2)O ?

How many moles are in 96 g O_(2)?

A mixture containing one mole of BaF_(2) and two mole of H_(2)SO_(4) will be neutralised by: