Calculate the number of atoms of each type that are present in `3.42 g` of sucrose `(C_(12) H_(22) O_(11))`.

Explanation

`Mw` of sucrose `= C_(12) H_(22) O_(11)`
`= 12 xx 12 + 1 xx 22 + 16 11`
`= 342 g`
a. 1 mol of sucrose `= 342 g = 12 mol of C`
`:. 3.42 g = (12)/(342) xx 3.42`
`= 0.12 mol of C = 0.12 xx 6.023 xx 10^(23) "atoms"`
`= 7.228 xx 10^(22) "atoms of" C`
b. `342 g` of Sucrose `= 22 mol of H`
`3.42 g` of sucrose `= (22)/(342) xx 3.42`
`= 0.22 mol of H`
`= 0.22 xx 6.023 xx 10^(23) `atoms
`=132.5 xx 10^(21)` atom of `H`
c. `342 g` of sucrose `= (11 xx 6.023 xx 10^(23))/(342) xx 3.42`
`= 66.25 xx 10^(21)` atoms of `O`