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The volume of a drop of water is 0.04 mL...

The volume of a drop of water is `0.04 mL`. How many `H_(2) O` molecules are there in a drop of a water? `d = 1.0 g mL`.

Text Solution

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Volume of 1 drop of `H_(2) O - 0.04 mL`
Weight of 1 drop of `H_(2) O =` Volume `xx` Density
`= 0.04 xx 1 = 0.04 g`
1 mole of `H_(2) O = 18 g = 6.023 xx 10^(23)` molecules
`:. 0.04 g = (6.023 xx 10^(23) xx 0.04)/(18) = 1.3384 xx 10^(21)` molecules
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