Calculate the number of molecules present in one drop of `H_(2) O` whose mass is `0.01 g`
b. Calculate the number of molecules leaving the liquid suface per second, if the same drop of water evaporates in one hour.

Explanation

a. `0.01 g of H_(2) O = (0.01)/(18) mol`
`= (0.01)/(18) xx 6.022 xx 10^(23)` molecules
b. Number of moleucles leaving per second
`= (3.345 xx 10^(20))/(60 x 60) = 9.293 xx 10^(16)` molecules