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An organic compound consists of 6.023 xx...

An organic compound consists of `6.023 xx 10^(23)` carbon atoms, `1.8069 xx 10^(24)` hydrogen atoms, and `3.0115 xx 10^(23)` oxygen atoms. What is its simplest formula?

Text Solution

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Mole of `C = (6.023 xx 10^(12))/(6.023 xx 10^(23)) = 1`
Moles of `H = (1.8069 xx 10^(24))/(6.023 xx 10^(23)) = 3`
Moles of `O = (3.0115 xx 10^(23))/(6.023 xx 10^(23)) = 0.5`
`C : H : O = 1 : 3 : 0.5 = 2 : 6 : 1`
Empirical formula `= C_(2) H_(6) O`
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