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2 g of a metal in H(2) SO(4) gives 4.51 ...

`2 g` of a metal in `H_(2) SO_(4)` gives `4.51 g` of the metal sulphate. The specific heat of metal is `0.057 cal g^(-1)`. Calculate the valency and atomic weight of metal.

Text Solution

Verified by Experts

Atomic weight `xx` Specific heat = 6.4
`a xx 0.057 = 6.4` ltbr. `a = 112.28`
Now,
Equivalent of metal = Equivalent of metal sulphate
`(2)/(E) = (4.51)/(E + 48)` `( :' Ew of SO_(4)^(2-) = 48)`
`:. E = 38.24`
`:.` Valency of metal `= ("Atomic weight")/("Molecular weight")`
`= (112.28)/(38.24)`
`= 2.93 ~~ 3` `( :'` valency is integre)
`:.` Exact atomic weight of metal `= Ew xx "Valency"`
`= 38.24 xx 3 = 114.72`
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