Calculate normality and molarity of the following:
a. `0.74 g` of `Ca(OH)_(2)` in `5 mL` of solution ltbRgt b. `3.65 g` of `HCl` in `200 mL` of solution
c. `1//10` mol of `H_(2) SO_(4)` in `500 mL` of solution.

Explanation

a. `:'` Equivalent of `Ca(OH)_(2) = (0.74)?(74//2) (Eq = (W)/(E))`
Volume of solution `= 5 mL`
`:. N = (0.74 xx 1000 xx 2)/(74 xx 5) = 4`
`:. M = (N)/("Valency") = (4)/(2) = 2`
b. `:'` Equivalent of `HCl = (3.65)/(36.5)`
and volume of solution `= 200 mL`
`:. N = (3.65 xx 1000)/(36.5 xx 200) = 0.5`
and `M = (N)/("Valency") = (0.5)/(1) = 0.5`
c. Equivalent of `H_(2) SO_(4) = (1)/(4) xx 2`
(`:' Eq = "Mole" xx "Volency"`)
Volume of solution `= 500 mL`
`:. N = (2 xx 1000)/(10 xx 500) = 0.4`
`M = (0.4)/(2) = 0.2`