In what ratio should you mix `0.2 M NaNO_(3)` and `0.1 M Ca (NO_(3))_(2)` solution so that in resulting solution the concentration of -ve ion is 50 % greater than the concentration of + ve ions?

Explanation

To solve the problem of mixing `0.2 M NaNO3` and `0.1 M Ca(NO3)2` such that the concentration of negative ions is 50% greater than the concentration of positive ions, we can follow these steps:

### Step 1: Identify the ions in the solutions
- **NaNO3** dissociates into Na⁺ and NO3⁻ ions.
- **Ca(NO3)2** dissociates into Ca²⁺ and 2 NO3⁻ ions.

### Step 2: Define the volumes of the solutions
Let:
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