What volume at water is requried to make `0.20 N` solution from `1600 mL` of `0.2050 N` solution?

Explanation

mEq of concentrated soution `= 1600 xx 0.2050 = 328`
Let after dilution volume becomes `V mL`
mEq of diluted solution `= 0.20 V`
`:. 328 = 0.20 xx V`
`V = 1640 mL`
Thus, the volume of water used to prepare `1640 m` of `0.20 N` solution `= 1640 - 1600 = 40 mL`