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What volume of 95% H(2) SO(4) by weight ...

What volume of 95% `H_(2) SO_(4)` by weight `(d = 1.85 g mL^(-1))` and what mass of water must be taken to prepare `100 mL` of 15% solution of `H_(2) SO_(4)` `(d = 1.10 g mL^(-1))`

Text Solution

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`{:(d = 1.85, d = 1.10),(V_(1) = ?, V_(2) = 100 mL),(M_(1)V_(1) =, M_(2)V_(2)):}`
`(95 xx 10 xx 1.85)/(98) xx V_(1) = (15 xx 10 xx 1.1)/(98) xx 100`
`V_(1) 9.4 mL`
Volume of `H_(2) O` added `= 100 - 9.4 = 90.6 mL`
Weight of `H_(2) O` added `= 90.6 xx 1 = 90.6 g` `(d_(H_(2)O) = 1)`
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