`49 g` of `H_(2) SO_(4)` is disslved in enough water to make one litre of a soltuion of density `1.049 g c c^(-1)`. Find the molarity, normality, moality, and mole fraction of `H_(2) SO_(4)` in the solution.

Answer

A

Explanation

i. `M = (W_(2) xx 100)/(Mw_(2) xx V_(sol) ("in" mL)) = (49 xx 1000)/(98 xx 1000) = 0.5 M`
ii. `m = (W_(2) xx 1000)/(Mw_(2) xx W_(1)) ({:(W_(1)=V_("Sol")xxd_("sol")-W_(2)),(=1000xx1.049-49),(=1000g):})`
`= (49 xx 1000)/(98 xx 1000) = 0.5 m`
iv. `X_(2) = (W_(2) // Mw_(2))/((W_(1))/(Mw_(1)) + (W_(2))/(Mw_(2))) = (49 // 98)/((100)/(18) + (49)/(98)) = (0.5)/(55.5 + 0.5)`
`(0.5)/(56) = 0.009`