If the law of constant compositon is true, what weights of calcium carbon, and oxygen are present in `1.5 g` of calcium carbonate, if a sample of calcium carbonate from another source contains the following percentage composition: `Ca = 40.0%, C = 12.0%`, and `O = 48.0%`?

Explanation

To find the weights of calcium, carbon, and oxygen present in 1.5 g of calcium carbonate (CaCO₃) based on the given percentage composition, we can follow these steps:

### Step 1: Understand the Composition
According to the law of constant composition, the percentage composition of elements in a compound remains the same regardless of the source. For calcium carbonate, the percentages are:
- Calcium (Ca) = 40.0%
- Carbon (C) = 12.0%
- Oxygen (O) = 48.0%

### Step 2: Calculate the Weight of Each Element
To find the weight of each element in 1.5 g of calcium carbonate, we will use the percentage composition.

#### Weight of Calcium:
\[ \text{Weight of Ca} = \left(\frac{40.0}{100}\right) \times 1.5 \, \text{g} = 0.6 \, \text{g} \]

#### Weight of Carbon:
\[ \text{Weight of C} = \left(\frac{12.0}{100}\right) \times 1.5 \, \text{g} = 0.18 \, \text{g} \]

#### Weight of Oxygen:
\[ \text{Weight of O} = \left(\frac{48.0}{100}\right) \times 1.5 \, \text{g} = 0.72 \, \text{g} \]

### Step 3: Summary of Results
Now, we can summarize the weights of each element in 1.5 g of calcium carbonate:
- Weight of Calcium (Ca) = 0.6 g
- Weight of Carbon (C) = 0.18 g
- Weight of Oxygen (O) = 0.72 g

### Final Answer:
- Calcium (Ca): 0.6 g
- Carbon (C): 0.18 g
- Oxygen (O): 0.72 g

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