Home
Class 11
CHEMISTRY
An element forms two oxides containing, ...

An element forms two oxides containing, 50% & 40% of oxygen respectively by weight of the element. Does these oxides illustrate the law of multiple proportions :-

Text Solution

Verified by Experts

The correct Answer is:
A
In one oxide:
`50g` of element combines with `50 g` of oxygen.
Therefor, `1 g` of element will combine with `1 g` of oxygen
In the other oxide:
`40 g` of element will combine with `60 g` of oxygen.
Therefore, `1 g` of element will combine with `64//40` or `1.5 g` of oxygen.
Thus, the weights of oxygen that combines with `1 g` of the element in the two oxides are in the ratio of `1 : 1.5` or `2:3,` which is a simple ratio. This illustrates the law of multiple proportions.
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS AND MOLE CONCEPT

    CENGAGE CHEMISTRY|Exercise Exercises Subjective (Limiting Reagent)|2 Videos

  • SOME BASIC CONCEPTS AND MOLE CONCEPT

    CENGAGE CHEMISTRY|Exercise Exercises Subjective (Empirical And Molecular Formulae)|4 Videos

  • SOME BASIC CONCEPTS AND MOLE CONCEPT

    CENGAGE CHEMISTRY|Exercise Ex 1.2 Fill In The Blanks|1 Videos

  • S-BLOCK GROUP 2 - ALKALINE EARTH METALS

    CENGAGE CHEMISTRY|Exercise Ex 5.1 Objective|2 Videos

  • STATES OF MATTER

    CENGAGE CHEMISTRY|Exercise Exercises (Ture False)|25 Videos

Similar Questions

Explore conceptually related problems

Hydrogen peroxide and water contain 5.93% and 11.2 % of hydrogen respectively. Show that the data illustrate law of multiple proportions.

An element forms two oxides containing respectively 53.33 and 36.36 percent of oxygen. These figures illustrate the law of

The oxide of an element contains 67.67% of oxygen. Equivalent weight of the element is

On analysis it was found that the black oxide of copper and red oxide of copper contain 80% and 89% of copper respectively. Show that this data is in accordance with law of multiple proportions.