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An impure sample of sodium chloride that...

An impure sample of sodium chloride that weighed `0.50 g` gave `0.90 g` of silver choride as precipitate on treatment with excess of silver nitrate solution. Calculate the percentage purity of the sample.

Text Solution

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The correct Answer is:
B
`NaCl + AgNO_(3) rarr AgCl + NaNO_(3)`
`23 + 35.5 = 58.5 g` `108 + 35.5 = 143.5 g`
`143.5 g of AgCl` is obtained from `58.5 g` of pure `NaCl`
`0.9 g of AgCl` is obtained from `= (58.5 xx 0.9)/(143.5)`
`= 0.36 g` of pure `NaCl`
% purity `= (0.36 xx 100)/(0.5) = 72%`
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