Equal weights of `X` (atomic weight = 36) and `Y` (atomic weight = 24) are reacted to form the compound `X_(2) Y_(3)`, which of the following is/are correct

Options

A. `X` is the limiting reagent
B. `Y` is the limiting reagen.
C. NO reactant is left over.
D. Mass of `X_(2)Y_(3)` formed is double the mass of `X` taken.

Answer

C, D

Explanation

(Let 'a' g of `X` and `Y` taken)
`underset({:("Initial moles""implies"),("Final moles" "implies"):})( ) underset({:((a)/(36)),(-):})(2X) + underset({:((a)/(24)),(-):})(3Y) rarr underset({:( ),((a)/(72)):})(X_(2) Y_(3))`
Since both `X` and `Y` are completely consumed, there is no limiting reagent.
Mole of `X_(2) Y_(3) = (a)/(72)`,
`(Mw "of" X_(2) Y_(3) = 2 xx 36 + 24 xx 3 = 144)`
Weight of `X_(2) Y_(3) = (a)/(72) xx 144 = 2a = 2 xx` Weight of `X`