The normality of `0.3 M` phosphorous acid `(H_(3) PO_(3))` is

Options

A. 0.1
B. 0.9
C. 0.3
D. 0.6

Explanation

To find the normality of 0.3 M phosphorous acid (H₃PO₃), we can follow these steps:

### Step 1: Understand the Concept of Normality
Normality (N) is defined as the number of equivalents of solute per liter of solution. For acids, normality can be calculated using the formula:
\[ \text{Normality} = \text{Molarity} \times \text{Basicity} \]

### Step 2: Identify the Molarity
We are given that the molarity of phosphorous acid (H₃PO₃) is 0.3 M.

### Step 3: Determine the Basicity of Phosphorous Acid
Basicity refers to the number of hydrogen ions (H⁺) that can be released by an acid. For phosphorous acid (H₃PO₃), it can release 2 H⁺ ions. Therefore, the basicity of H₃PO₃ is 2.

### Step 4: Calculate Normality
Using the formula for normality:
\[ \text{Normality} = \text{Molarity} \times \text{Basicity} \]
Substituting the values we have:
\[ \text{Normality} = 0.3 \, \text{M} \times 2 = 0.6 \, \text{N} \]

### Conclusion
The normality of 0.3 M phosphorous acid (H₃PO₃) is **0.6 N**.

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