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Dissolving 120g of urea (Mw = 60) in 100...

Dissolving `120g` of urea `(Mw = 60)` in `1000 g` of water gave a solution of density `1.15 g mL^(-1)`. The molarity of solution is:

A

`1.78 M`

B

`2.00 M`

C

`2.05 M`

D

`2.22 M`

Text Solution

Verified by Experts

The correct Answer is:
C
`V_("Sol") = ((120 + 1000))/(1.15) mL`
`M = (W_(2) xx 1000)/(Mw_(2) xx V_("sol")) = (120 xx 1000)/(60 xx 1120//1.15) = (2 xx 115)/(12) = 2.05 M`
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