Silver (atomic weight `108 g mol^(-1))` has a density of `10.5 g cm^(-3)`. The number of silver atoms on a surfaces of area `10^(-12) m^(2)` can be expressed in scientific notation as `Y xx 10^(-x)`, The value of `x` is …….

Explanation

Density `= 10.5 g c c^(-1)`
This measn `10.5 g` silver is present in `1 cm^(3)`.
`(10.5)/(108)` mol silver is present in `1 cm^(3)`.
`(10.5)/(108) N` silver atoms present in `1 cm^(3)`
`.^(3)sqrt((10.5)/(108) N)` silver atoms present in `1 cm`
`(.^(3)sqrt((10.5)/(108) N))^(1//2)` silver atoms present is `1 cm^(2)`.
`10^(-12)` is equal to `10^(-8) cm^(2)`.
`(.^(3)sqrt((10.5)/(108) N))^(1//2) xx 10^(-8)` silver atoms present in `10^(-12) m^(2)`.
On solving, we get `1.5 xx 10^(-7) = Y xx 10^(-x)`
`:.x = 7`