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Calculate the molality of 1 L solution o...

Calculate the molality of `1 L` solution of `93% H_(2)SO_(4)` (Weight/volume) The density of the solution is `1.84 g`.

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The correct Answer is:
A, B, D
Density `= 1.84 g L^(-1)`
Mass of `100 mL` solution `= 100 xx 1.84 = 184 g`
Mass of `H_(2) SO_(4)` in `100 mL` solution `= 93 g`
Mass of water is `100 mL` solution `= 184 - 93 = 91 g`
Molality `= (93)/(98) xx (1)/(91) xx 1000 = 10.428`
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