Home
Class 11
CHEMISTRY
Calculate the amount of calcuium oxide r...

Calculate the amount of calcuium oxide required when it reacts with `852 g` of `P_(4) O_(10)`.

Text Solution

Verified by Experts

The correct Answer is:
A
`6CaO + P_(4) O_(10) rarr 2Ca_(3) (PO_(4))_(2)`
`6CaO -= P_(4)O_(10)`
`(6 (40 + 16))/(W) = ((31 xx 4) + (16 xx 10))/(852)`
or `W = 1008 g`
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS AND MOLE CONCEPT

    CENGAGE CHEMISTRY|Exercise Archives Fill In The Blanks|4 Videos

  • S-BLOCK GROUP 2 - ALKALINE EARTH METALS

    CENGAGE CHEMISTRY|Exercise Ex 5.1 Objective|2 Videos

  • STATES OF MATTER

    CENGAGE CHEMISTRY|Exercise Exercises (Ture False)|25 Videos

Similar Questions

Explore conceptually related problems

In P_(4)O_(10) ,

How many grams of CaO are required to neutralise 852 g of P_(4)O_(10)?

(a) What amount of CaO in grams is required to neutralise 852g of P_(4)O_(10) . (b) Write the structure of P_(4)O_(10) (b) Write the structure of P_(4)O_(10) .

What happen when CaO reacts with P_4O_10 :-

Calculate the moles of KMnO_(4) required to react completely with 2 m and 1500 mL of K_(2)C_(2)O_(4)H_(2)C_(2)O_(4) in acidic medium.