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A particle is projected from ground with...

A particle is projected from ground with velocity `50 m//s` at `37^@` from horizontal. Find velocity and displacement after 2 s. `sin 37^@ = 3/5`.

Text Solution

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The correct Answer is:
A, D
`u = (40hati + 30hatj) m//s, a= (-10hatj) m//s^2, t=2 sec`
Now, `v=u+at and s = ut + 1/2 at^2`
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