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A particle is projected from ground with...

A particle is projected from ground with initial velocity `u= 20(sqrt2)m//s at theta = 45^@`. Find
(a) R,H and T,
(b) velocity of particle after 1 s
(c) velocity of particle at the time of collision with the ground (x-axis).

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D
(a) `R = (u^2 sin 2theta)/g, H = (u^2sin^2theta)/(2g)`
and `T= (2usintheta)/g`
Here, `u= 20(sqrt 2) m//s and theta = 45^@`
(b) v=u+at
where, ` u=(20hati + 20hatj) m//s`
and `a= (-10hatj) m//s^2`
(C ) Horizontal component remains unchanged `(=20hati)` and vertical component is reversed in direction `(=20hatj)` .
`v= (20hati - 20hatj) m//s`
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