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A bullet fired at an angle of 30^@ with ...

A bullet fired at an angle of `30^@` with the horizontal hits the ground 3.0 km away. By adjusting its angle of projection, can one hope to hit a target 5.0 away? Assume the muzzle speed to be fixed and neglect air resistance.

A

Yes

B

No

C

Cannot be determined

D

None of the above

Text Solution

Verified by Experts

The correct Answer is:
A
`R = (u^2sin60^@)/g = 3 km`
`rArr u^2/g = R_(max) = 3/(sin60^@)`
`=2(sqrt3) km`
Since, `R_(max) lt 5 km`
So, it can't hit the target at 5 km.
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