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A particle moves in the plane xy with co...

A particle moves in the plane xy with constant acceleration 'a' directed along the negative y-axis. The equation of motion of the particle has the form `y= px - qx^2` where p and q are positive constants. Find the velocity of the particle at the origin of co-ordinates.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
Comparing with,
`y= xtan theta - (gx^2)/(2u^2) (1+tan^2theta)`
`tan theta = b, g=a`
and `g/(2u^2) (1+tan^2theta) = c`
`:. (a(1+b^2))/(2u^2) = c`
`:. u = u=sqrt((a(1+b^(2)))/(2c))`
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