Home
Class 11
PHYSICS
A body is desplaced from origin to (2m, ...

A body is desplaced from origin to `(2m, 4m)` under the following two forces:
(a) `F=(2^hati + 6^hatj)N`, a constant force
(b) `F(2x^hati + 3y^(2)hatj)N`
Find word done by the given forces in both cases.

Text Solution

Verified by Experts

The correct Answer is:
B
(a) `F=(2hati + 6hatj)N`
`dr=(dxhati + dyhatj)`
`:. fdr= 2 dx + 6 dy`
`W =int_((0.0))^((2m.4m))F.dr = int_((0.0))^((2m.4m))(2dx + 6dy)`
`=[2x + 6y]_(0,0)^(2m,4m) =(2xx2 + 6xx4)`
`=28J`
Promotional Banner

Topper's Solved these Questions

  • WORK, ENERGY & POWER

    DC PANDEY|Exercise TYPE2|1 Videos

  • WORK, ENERGY & POWER

    DC PANDEY|Exercise Miscellaneous Example|6 Videos

  • WORK, ENERGY & POWER

    DC PANDEY|Exercise Level 2 Comprehension Based|2 Videos

  • WAVE MOTION

    DC PANDEY|Exercise Integer Type Question|11 Videos

  • WORK, ENERGY AND POWER

    DC PANDEY|Exercise MEDICAL ENTRACES GALLERY|33 Videos

Similar Questions

Explore conceptually related problems

A force of (3 hati + 4 hatj) Newton acts on a body and it by (3 hati + 4 hatj)m . The work done by the force is

An object is displaced from point A(2m,3m,4m) to a point B(1 m,2 m,3 m) under a constant force F=(2hati + 3hatj + 4hatk)N . Find the work done by this force in this process.

A body is displaced from (0,0) to (1 m, 1m) along the path x = y by a force F=(x^(2) hatj + y hati)N . The work done by this force will be

An object has a displacement from position vector vecr_(1) = (2 hat i+3hatj)m to vecr_(2) = (4hat i + 6 hat j)m under a force vec F = (3x^(2) hati + 2y hatj)N , then work done by the force is

An object is displaced along a straight line from point A (2 m, 1 m , 5m) to B (4m, 2m, 1m) under the action of a force vecF=(xhati+3y^(2)hatj+2zhatk)N Find work done by this force.

A force F=(3thati + 5hatj)N acts on a body due to which its displacement varies as S=(2t^(2)hat-5hatj)m . Work done by these force in 2 s is .

A body is displaced from, r_A=(2hati + 4hatj-6hatk) m to r_(B)=(6hati-4hatj + 2hatk)m under a constant force, F=(2hati + 3hatj-hatk)N . Find the work done.

A block is displaced from (1m, 4m, 6m) to (2hati+3hatj-4hatk) m under a constant force F=(6hati-2hatj + hatk) N . Find the work done by this force.

A particle moves from point P(1,2,3) to (2,1,4) under the action of a constant force F=(2hati+hatj+hatk)N . Work done by the force is