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A particle is placed at the origin and a...

A particle is placed at the origin and a force F=Kx is acting on it (where k is a positive constant). If `U_((0))=0`, the graph of `U (x)` verses x will be (where U is the potential energy function.)

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The correct Answer is:
A
From `F=-(dU)/(dx)`
`int_(0)^(U(x))dU =-int_(0)^(x)Fdx =-int_(0)^(x)(kx) dx`
` :. U(x) =-(kx2)/(2) as U(0) =0`
Therefore, the correct option (a).
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