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A flywheel of moment of inertia 5.0kg-m^...

A flywheel of moment of inertia `5.0kg-m^(2)` is rotated at a speed of `10rad//s` because of the friction at the axis it comes to rest in 10s. Find the average torque of the friction.

Text Solution

Verified by Experts

`0=omega_(0)-alphat`
`impliesalpha=(omega_(0))/(t)=(10)/(10)`
`=1rad//s^(2)`
`tau=Ialpha=5N-m`
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